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思路:① 找初始左边界:第一个 nums[i] nums[i+1];② 找初始右边界:最后一个 nums[i] < nums[i-1];③ 求 [left,right] 内 min、max;④ 向左扩展:nums[left-1] minVal 则 left--;⑤ 向右扩展:nums[right+1] < maxVal 则 right++。长度 = right - left + 1。

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Greater Than (2): Everything in this space must be greater than 2. The answer is 4-4, placed vertically.。业内人士推荐旺商聊官方下载作为进阶阅读

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